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in Algebraic Expressions by (56.3k points)

Factorize:

32a3 + 108b3.

1 Answer

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Best answer

32a3 + 108b3 

= 4(8a3 + 27b3

= 4((2a)3 +(3b)3)   [a3 + b3 = (a + b)(a2 – ab + b2)]

= 4[(2a + 3b)((2a)− 2a x 3b + (3b)2)] 

= 4(2a + 3b)(4a2 − 6ab + 9b2)

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