Given ×4 on set S = {0, 1, 2, 3}
Now,
1 ×4 1 = remainder obtained by dividing 1 × 1 by 4
= 1
0 ×4 1 = remainder obtained by dividing 0 × 1 by 4
= 0
2 ×4 3 = remainder obtained by dividing 2 × 3 by 4
= 2
3 ×4 3 = remainder obtained by dividing 3 × 3 by 4
= 1
Therefore, the composition table is below:
x4 |
0 |
1 |
2 |
3 |
0 |
0 |
0 |
0 |
0 |
1 |
0 |
1 |
2 |
3 |
2 |
0 |
2 |
2 |
2 |
3 |
0 |
3 |
2 |
1 |