Given x6 on set S = {0,1,2,3,4,5}.
Now,
1 ×6 1 = remainder obtained by dividing 1 × 1 by 6
= 1
3 ×6 4 = remainder obtained by dividing 3 × 4 by 6
= 0
4 ×6 5 = remainder obtained by dividing 4 × 5 by 6
= 2
Therefore, the composition table is below
| x6 |
0 |
1 |
2 |
3 |
4 |
5 |
| 0 |
0 |
0 |
0 |
0 |
0 |
0 |
| 1 |
0 |
1 |
2 |
3 |
4 |
5 |
| 2 |
0 |
2 |
4 |
0 |
2 |
4 |
| 3 |
0 |
3 |
0 |
3 |
0 |
3 |
| 4 |
0 |
4 |
2 |
0 |
4 |
2 |
| 5 |
0 |
5 |
4 |
3 |
2 |
1 |
