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Calculate the pH of 0.3 g of NaOH dissolved in water to give 200 mL of solution.

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pH of 0.3g of NaOH in 200 mL of solution

= -(log 3.75 - 2 log 10)

= (2 - log 3.75)

= (2 - 0.574)

= 1.426

pH = 14 - pOH

= 14 - 1.426

= 12.574

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