Question

At what angle should a cyclist lean over from the vertical while negotiating a curve of radius 58m with a speed of 15 km/hour?

Answer 1

The angle of banking is given by,

tanθ = \(\frac {v^2}{rg}\)

Here, v = \(\frac {15000}{60 \times 60} \) = 4.17 ms^-1

∴ tanθ = \(\frac {(4.17)^2}{58 \times 9.8}\)

= 0.03059

θ = tan^-1 (0.03059)

= 1°45’.