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The pH of 0.1 M solution of cyanic acid (HCNO) is 2.34. Calculate the ionization constant of the acid and its degree of ionization in the solution.

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Calculation of degrees of dissociation (α) in solution

pH = 2.34 or log\(\bigg[\frac{1}{H^+}\bigg]\) = 2.34

\(\bigg[\frac{1}{H^+}\bigg]\) = Antilog 2.34 or [H+]

= Antilog (-2.34)

[H+] = Antilog (3.66) = 4.571 x 10-3 M

α = \(\frac{[H^+]}{C}\) = \(\frac{(4.571\times 10^{-3}\,M)}{(0.1\,M)}\)

= 4.571 x 10-2 = 0.04571 M

Calculation of the ionization constant of the acid

[H+] = (Ka x C)1/2

or, [H+]2 = (Ka x C)

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