Question

A golf ball leaves the tee with a velocity of 50ms^-1 at an angle of 300 with the horizontal. Find its

1. time of flight

2. Range of projectile and

3. The velocity with which it hits the ground at the end of its flight.

Answer 1

u = 50m/s, θ = 30°.

1. Time of flight

T = \(\frac{2usin \theta}{g}\) 

= \(\frac{ 2 \times 50 \times sin(30)}{9.8}\)

= 5.10 s

2. Range R = \(\frac{u^2sin 2 \theta}{g}\)

= \(\frac{ 50^2sin \times(2\times30° )}{9.8}\)

= 220.92 m

3. Velocity at the end = velocity of projection = 50 m/s.