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Balance the equation by ion electron method.  CrO4^– + H2O2 →CrO4^2- in basic solution.

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Balance the equation by ion electron method. 

CrO4– + H2O2 →CrO42- in basic solution.

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[2OH- + CrO-3 → CrO42- + e- + H2O]   x 2 …(i)

2e- + H2O2 → 2OH-  …(ii) 

(Add (i) & (ii))

2OH- + 2CrO3- + H2O2 → 2CrO42- + 2H2O

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