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Write the cell reactions for Zn|Zn2+(IM)||Cd2+(IM)|Cd E°Zn2+/Zn = -0.76V, E°Cd2+/Cd = 0.40V.

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At anode:-

Zn(s) → Zn2+(aq) + 2e- (Oxidation)

At cathode:-

Cd2+(aq) + 2e- → Cd(s) (Reduction)

Zn(s) + Cd2+(aq) → Zn2+(aq) + Cd(s)

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