Writing the oxidation number of each atom above its symbol we have,
Here, in the reaction, the oxidation number of copper decreases from +1 in Cu2O or Cu2S to 0 in copper metal, therefore, copper is reduced and is .oxidizing agent or oxidants. Further, the oxidation number of S increases from -2 in Cu2S to +4 in SO2. Therefore, sulphur is oxidized. Thus, it is reducing agent of reductant.