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Identify the oxidant and reductant in the reactions:

10H+(aq) + 4Zn(s) + NO3(aq) → 4Zn2+(aq) + NH4+ + 3H2O(l)

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Writing the O.N. of all the atoms above their symbols, we have

O.N. of Zn changes from zero in Zn to +2 in Zn2+ and, therefore, it is oxidized and hence Zn acts as a reductant.

The O.N. of N decreases from +5 in NO3 to -3 in NO4+ and, therefore, it is reduced and hence NO3 acts as the oxidant.

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