LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
in Chemistry by (66.3k points)

Identify the oxidant and reductant in the reactions:

I2(g) + H2S(g) → 2HI(g) + S(s)

1 Answer

+1 vote
by (64.3k points)
selected by
Best answer

Writing the ON of all the atoms above their symbols, we have

The ON of I2 decreases from zero in I2 to -1 in HI, therefore, I2 is reduced and hence it acts as on oxidant. 

The O.N. of S increases from -2 in H2S to zero in S, therefore, H2S is oxidized and hence it acts as the reductant.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.