Fewpal
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Identify the oxidant and reductant in the reactions:

I2(g) + H2S(g) → 2HI(g) + S(s)

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Writing the ON of all the atoms above their symbols, we have

The ON of I2 decreases from zero in I2 to -1 in HI, therefore, I2 is reduced and hence it acts as on oxidant. 

The O.N. of S increases from -2 in H2S to zero in S, therefore, H2S is oxidized and hence it acts as the reductant.

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