Question

A hammer of mass 1 kg moving with a speed of 6 ms^-1 strikes a wall and comes to rest in 0.1 s. Find the
1. Impulse
2. Retarding force on the hammer
3. Retardation

Answer 1

1. The initial momantum of the hammer is,

m × v = 1 kg × 6 ms^-1

= 6 kg ms^-1

= 6 Ns

Impulse = F. t = Δ P

= 0 – mv

= – 6 Ns.

2. The force on the hammer

F = Impulse/time

= 6Ns/0.1s

= 60 N.

3. Retardation = a 

= F/m 

= 60N/1kg

= 60 ms^-2.