Given : ∠AOC and ∠BOC form a linear pair.
=> a + b = 180° …..(1)
a – 2b = 30° …(2)
On subtracting equation (2) from (1), we get
a + b – a + 2b = 180° – 30°
3b = 150°
b = 150/3
b = 50°
Since, a – 2b = 30°
a – 2(50) = 30°
a = 30° + 100°
a = 130°
Therefore, the values of a and b are 130° and 50° respectively.
