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Balance the following equation by ION-Electron method: Zn(s) + NO4^+ → Zn^2+(aq) + NH4^+(aq) + H2O(l)

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Balance the following equation by ION-Electron method:

Zn(s) + NO4+ → Zn2+(aq) + NH4+(aq) + H2O(l)

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Oxidation half reaction

Multiply (1) equation by 4 to equalize the no. of electrons in both. Add both half reactions

4Zn(s) → Zn2+(aq) + 8e-   ...(3)

then (3) + (2) is

4Zn(s) + NO3-(aq) + 10H+(aq) → 4Zn2+(aq) + NH4+(aq) + 3H2O(l)

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