Let ABC be a triangle such that AD is the angular bisector of exterior vertical angle, ∠EAC and AD ∥ BC.
From figure,
∠1 = ∠2 [AD is a bisector of ∠ EAC]
∠1 = ∠3 [Corresponding angles]
and ∠2 = ∠4 [alternative angle]
From above, we have ∠3 = ∠4
This implies, AB = AC
Two sides AB and AC are equal.
Δ ABC is an isosceles triangle.