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If cos A = 3/5 , find the value of 9 cot^2A – 1. (a) 1 (b) 16 65 (c) 65 16 (d) 0

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If cos A = 3/5 , find the value of 9 cot2A – 1. 

(a) 1 (b) 16/65 (c) 65/16 (d) 0

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CosA=b/h=3/5
b=3k
h=5k
p=√5k^2-3k^2
p=4k
Now,
9cot^2A-1
9b/p^2-1
9•3k/4k^2-1
9•9k/16k-1
81k/16k-1
65k/16k
65/16 ans(c)
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The correct option is (c).

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