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If a cos^3θ + 3a cos θ sin^2θ = m and a sin^3θ + 3a cos^2θ sin^2 θ = n, then (m + n)^2/3 + (m – n)^ 2/3 is equal to

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If a cos3θ  + 3a cos θ  sin2θ  = m and a sin3θ  + 3a cos2θ sin2 θ  = n, then (m + n)2/3 + (m – n) 2/3 is equal to 

(a) a2/3 (b) 2a1/3 (c) 2a2/3 (d) a1/3

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The correct option is (c).

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