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0 votes
1.8k views
in Linear Equations by (56.3k points)

From the choices given below, choose the equation whose graph is given fig:

(i) y = x + 2 (ii) y = x – 2 (iii)y = – x + 2 (iv) x + 2y = 6

1 Answer

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Best answer

Given: (-1, 3) and (2, 0) are the solution of one of the following given equations.

Check which equation satisfy both the points.

(i) y = x + 2 

Putting, x = -1 and y = 3 

3 ≠ – 1 + 2 

L.H.S ≠ R.H.S 

Putting, x = 2 and y = 0 

0 ≠ 4 

L.H.S ≠ R.H.S 

Thus, this solution does not satisfy the given equation.

(ii) y = x – 2 

Putting, x = -1 and y = 3 

3 ≠ – 1 – 2 

L.H.S ≠ R.H.S 

Putting, x = 2 and y = 0 

0 = 0 

L.H.S = R.H.S 

Thus, the given solutions does not satisfy this equation completely. 

(iii) y = – x + 2 

Putting, x = – 1 and y = 3 

3 = – ( – 1 ) + 2 

L.H.S = R.H.S 

Putting x = 2 and y = 0 

0 = -2 + 2 

0 = 0 

L.H.S = R.H.S 

Therefore, (0, 2) and (-1,3) satisfy this equation. 

Hence, this is the graph for equation y = -x + 2.

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