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Calculate the oxidation number of the element in the case K4MO2Cl8

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Calculate the oxidation number of the element in the case

K4MO2Cl8

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x be ON to be find K4MO2Cl8 = 4(+1) + (x)2 + 8(-1) = 0 

4 + 2x – 8 = 0 

=> 2x – 4 = 0 

=> x = +2

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