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A pump is used to fill a tank 6m × 3m × 2m in half an hour. If the average height to which water to be lifted from the well is 110m, find the horsepower of the engine.

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Volume of the tank = 6 × 3 × 2 = 36m3

∴ mass of water to be lifted

= V × d = 36 × 103 kg

∴ Work done = mg × h

= 36 × 103 × 9.8 × 110

Power of the pump = \(\frac{w}{t}\)

= \(\frac{36 \times 9.8\times1.1 \times 10^5}{30 \times60}\)= 0.216 × 105W

=\(\frac{0.216\times 10^5}{30 \times746}\)\(\frac{21600}{746}\)

28.9 HP.

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