Question

If A = diag(2 -5 9), B = diag(1 1 -4) and C = diag(-6 3 4), find

(i) A – 2B

(ii) B + C – 2A

(iii) 2A + 3B – 5C

Answer 1

(i) Given the diagonal of each

A = diag (2 -5 9), B = diag (1 1 -4) and C = diag (-6 3 4)

So,

(ii) Given as

A = diag (2 -5 9), B = diag (1 1 -4) and C = diag (-6 3 4)

So,

Compute B + C – 2A

(iii) Given the diagonal

A = diag (2 -5 9), B = diag (1 1 -4) and C = diag (-6 3 4)

Let us find 2A + 3B - 5C

considering 2A + 3B – 5C