Question

Sample of hydrogen peroxide solution is 1.5 M. If it is to be labelled ‘X’ volume; what is the value of ‘X’

Answer 1

Mass of H₂O₂ per liter = 1.5 × 34 = 51 g

68 g of H₂O₂ at STP gives 22.4 L of O₂

51g of H₂O₂ gives at STP = \(\frac{22.4\times51}{68}\)

= 16.8 L of H₂O₂ that has 51g of H₂O₂ will give 16.8 L of O₂

Hence value of X is 16.8 L.

∴ The given sample of H₂O₂ is 16.8 Vol.