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In figure, Δ PQR is an isosceles triangle with PQ = PR and m∠PQR=35°. Find m∠QSR and m∠QTR.

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Given: ΔPQR is an isosceles triangle with PQ = PR and m∠PQR = 35° 

In ΔPQR: 

∠PQR = ∠PRQ = 35° (Angle opposite to equal sides) 

Again, by angle sum property 

∠P + ∠Q + ∠R = 180°

∠P + 35° + 35° = 180°

∠P + 70° = 180° 

∠P = 180° – 70° 

∠P = 110° 

Now, in quadrilateral SQTR, 

∠QSR + ∠QTR = 180° (Opposite angles of quadrilateral) 

110° + ∠QTR = 180° 

∠QTR = 70°

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