The weight 2N of the bar acts at its midpoint D. Let C be the position of the knife edge and W be the weight suspended at the end A which keeps the bar horizontal.
Taking moments about C
W × AC = 2 × CD
W × 0.8 = 2 × 1.2
W = \(\frac{2\times 1.2}{0.8}\)
= 3 N.
To keep the bar horizontal the weight to be suspended is 3 N.