Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
621 views
in Physics by (49.4k points)

A uniform bar 4 metres long and weighing 2 N is resting on a knife edge at 0.8m from one end. What weight suspended from the end to keep the bar horizontal?

1 Answer

+1 vote
by (53.7k points)
selected by
 
Best answer

The weight 2N of the bar acts at its midpoint D. Let C be the position of the knife edge and W be the weight suspended at the end A which keeps the bar horizontal. 

Taking moments about C

W × AC = 2 × CD

W × 0.8 = 2 × 1.2

W = \(\frac{2\times 1.2}{0.8}\)

= 3 N.

To keep the bar horizontal the weight to be suspended is 3 N.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...