Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
562 views
in Continuity and Differentiability by (58.4k points)

Solve: \(\frac{sin(ax + b)}{cos(cx + d)}\)

1 Answer

+1 vote
by (53.2k points)
selected by
 
Best answer

\(y = \frac{sin(ax + b)}{cos(cx + d)}\)

\(\frac{dy}{dx} = \frac{cos(cx + d)\times cos(ax + b)\times a - sin(ax + b) \times - sin(cx + d) \times c}{cos^2(cx + d)}\)

\(= \frac{acos(cx + d)cos(ax + b) + csin(ax + b)sin(cx + d)}{cos^2(cx + d)}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...