Mass of big structure = 50,000 kg
Net force = (5 × 104 × 9.8)N
= 4.9 × 105 N = FB
Since it is supported by four cylinders the weight is equally distributed.
Force (F) on each cylinder is
F = \(\frac {FB}{4}\) = 122500 N
Young’s Modulus = Y
∴ Compressional strain of each column is given by,
Here, F = 122500 N
A = π(0.6)2 – π(0.3)2 = π(0.36 – 0.09)
= 0.27π = 8.48 × 10-1 m2
Y = 2 × 1011 N m-2 (Standard Values)
∴ Strain = \(\frac {122500}{(0.27π) \, (2 \times 10^{11})}\)
= 7.22 × 10-7
Thus the compressional strain per cylinder is 7.22 × 10-7.