Mass of big structure = 50,000 kg

Net force = (5 × 10^{4 }× 9.8)N

= 4.9 × 10^{5 }N = F_{B}

Since it is supported by four cylinders the weight is equally distributed.

Force (F) on each cylinder is

F = \(\frac {FB}{4}\) = 122500 N

Young’s Modulus = Y

∴ Compressional strain of each column is given by,

Here, F = 122500 N

A = π(0.6)^{2} – π(0.3)^{2} = π(0.36 – 0.09)

= 0.27π = 8.48 × 10^{-1 }m^{2}

Y = 2 × 10^{11} N m^{-2} (Standard Values)

∴ Strain = \(\frac {122500}{(0.27π) \, (2 \times 10^{11})}\)

= 7.22 × 10^{-7}

Thus the compressional strain per cylinder is 7.22 × 10^{-7.}