# A piece of copper having a rectangular cross-section of 15.2 mm × 19.1 mm is

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A piece of copper having a rectangular cross-section of 15.2 mm × 19.1 mm is pulled in tension with 44,500 N force, producing only elastic deformation. Calculate the resulting strain?

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F = 44,500 N

Strain = ?

Length = 19.1 mm, Breath = 15.2 mm

Area = A = 19.1 × 15.2 × 10-6m2

= 2.98 × 10-4 m2

G = 42 × 109 Nm-2

We have, G = $\frac{F}{A \times strain}$

∴ Strain = $\frac {F}{G \times A}$

$= \frac{44,500}{2.98 \times 10^{-4} \times 42 \times 10^{9}}$

= 3.65 × 10-3.