Question

The Young’s modulus of a material is Y. It has an area A and length ‘L'. Now if a is made \(\frac {A}{16}\)and length L/2. What is the new Young’s modulus?

Answer 1

Even though the value of Young’s modulus is given by, Y = \(\frac{F}{A}\) .\(\frac{I}{ΔI}. \)

It is only material dependent. It is constant for the given wire irrespective of its dimension. So, the new value of Young’s modulus is Y.