Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
464 views
in Surface Areas And Volumes by (56.3k points)

The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 cm3 of wood has a mass of 0.6 gm.

1 Answer

0 votes
by (30.5k points)
selected by
 
Best answer

Let r and R be the inner and outer radii of cylindrical pipe.

Inner radius of a cylindrical pipe (r) = \(\frac{24}{2}\) = 12 cm 

Outer radius of a cylindrical pipe (R) = \(\frac{24}{2}\) = 14 cm 

Height of pipe (h) = length of pipe = 35 cm 

Mass of pipe = volume x density = π(R2 – r2)h 

= \(\frac{22}{7}\)(142 – 122)35 

= 5720 

Mass of pipe is 5720 cm3 

Mass of 1 cm3 wood = 0.6 gm

Therefore, mass of 5720 cm3 wood = 5720 x 0.6

= 3432 gm 

= 3.432 kg

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...