Let r and R be the inner and outer radii of cylindrical pipe.
Inner radius of a cylindrical pipe (r) = \(\frac{24}{2}\) = 12 cm
Outer radius of a cylindrical pipe (R) = \(\frac{24}{2}\) = 14 cm
Height of pipe (h) = length of pipe = 35 cm
Mass of pipe = volume x density = π(R2 – r2)h
= \(\frac{22}{7}\)(142 – 122)35
= 5720
Mass of pipe is 5720 cm3
Mass of 1 cm3 wood = 0.6 gm
Therefore, mass of 5720 cm3 wood = 5720 x 0.6
= 3432 gm
= 3.432 kg