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The length of a metal is L1 when a force is F1 is applied on it and its length is L2 when applied force is F2. Find the original length of wire.

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We know that Y = \(\frac {Fl}{A∆l}\)

Let original length be L. Then,

L1 = L + ∆l1

L2 = L + ∆l2

Since, Y is a constant,

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