Question

In a cricket match, a batsman hits a boundary 6 times out of 30 balls he plays. Find the probability that on a ball played: 

(i) He hits boundary

(ii) He does not hit a boundary.

Answer 1

Total number of balls played by a player = 30 

Number of times he hits a boundary = 6

Number of times he does not hit a boundary 

= 30 – 6 

= 24 

We know, 

Probability of an event = (Number of Favorable outcomes) / (Total Numbers of outcomes) 

Now, 

(i) Probability (he hits boundary) = (Number of times he hit a boundary) / (Total number of balls he played) 

= \(\frac{6}{30}\)

= \(\frac{1}{5}\) 

(ii) Probability that the batsman does not hit a boundary 

= \(\frac{24}{30}\)

= \(\frac{4}{5}\)