In order to check whether 6n can end with the digit 0 for any natural number n, let us find the factors of 6.
It’s seen that the factors of 6 are 2 and 3.
So, 6n = (2 x 3)n
6n =2n x 3n
Since, the prime factorization of 6 does not contain 5 and 2 as its factor, together. We can thus conclude that 6n can never end with the digit 0 for any natural number n.