Area of the box
= A = 4 × (0.6 × 0.4) + 2 × (0.4 × 0.4) = 1.28m2
d = 0.04m
k= 0.08wm-1K-1
L= 3.36 × 105Jkg-1
Let Q be the heat transmitted per second.
To melt 1 kg of ice, 3.36 × 105J of heat is required
∴ Rate at which ice melts
\(\frac{69.12}{3.36 \times 10{^-5}}\)
= 20.57 × 10-5kgs-1.