Question

Calculate the rate at which heat is lost through a glass window of area 0.1m² thickness 4mm when the temperature inside is at 40°c and outside is -5°c. Co-efficient of thermal conductivity of a glass is 1.1 wm^-1k^-1.

Answer 1

A= 0.1m²

d = 4mm = 4 × 10^-3

m = 0.004m

θ₁ = 40°C

θ₂ = -5°c

k = 1.1 Wm^-1k^-1

Heat lost through the glass window is

= 1237.5J.