Question

A metal rod 0.3m long & 0.02m in diameter has one end at 100°C & other end at 0°C. Calculate the total amount of heat conducted in 2 minutes. Given k = 385 JS^-1m^-1K^-1.

Answer 1

l = 0.3m,

d = 0.02m

∴ r = 0.01m

θ₁ = 100°C

θ₂ = 0°C

t = 2 minutes = 120 S

k = 385 JS^-1m^-1K^-1 .

Q = ?

t= π r² = 3.142 × 0.012 = 3.142 × 10⁴m²

4.8 × 10³ J