From ideal gas law
PV = nRT
Here P = atm = 1. 013 × 105 Pa.
V = Volume = 25 m3
T = Temperature = 27°C = 300k
n = no of moles of gas
R = Gas constat = 8. 314 J mol-1 k-1
= 0.01015 × 105 =1015 mol
Since 1 mol ≅ 6. 023 × 1023 molecules
N = 1015 mol ≅ 6.023 × 1023 × 1015
N = 6.113 × 1026 molecules.
∴ The total no of molecules in the given room is 6.113 × 1026.