\(\frac{31\pi}{3}\)
= sin \(10\pi + \frac{1}{3} \pi\)
= sin \((5 \times (2\pi) + \frac{1}{3} \pi)\) [Values of sin x repeats after a interval of \(2\pi\), hence ignoring \(5 \times (2\pi)\)]
= sin \((\frac{1}{3} \pi)\)
= sin \((\frac{1}{3} \times 180^0)\)
= sin 60o
= \(\frac{\sqrt3}{2}\)
