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The acceleration due to gravity on the surface of moon is 1.7 m s2. What is the time period of a simple pendulum on the surface of moon if its time period on the surface of earth is 3.5 s? (g on the surface of earth is 9.8 m s-2 )

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gm =1.7 ms-2 ge = 9.8 ms-2 Te = 3.5 s

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