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in Definite Integrals by (58.4k points)

∫e-3x(cosx – 3sinx)dx is equal to

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∫e-3x(cosx – 3sinx) dx

∫ e-3x (-3sinx + cosx) 

f(x) = sinx,f'(x) = cosx 

∫e-3x(-3sinx + cosx) 

= e-3xsinx + C

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