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in Physics by (49.4k points)

A 0.2 kg of mass hangs at the end of a spring. When 0.02 kg more mass is added to the end of the spring, it stretched 7cm more. If the 0.02 kg mass is removed, what will be the period of vibration of the system?

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Best answer

Mass added m = 0.02 

Length stretched x = 7 cm = 0.07 m

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