Question

For the travelling harmonic wave y(x,t) = 2 cos 2π (10t – 0.0080 x + 0.35) where x and y are In centimetre and t In seconds. Calculate the phase difference between oscillatory motion of 2 points separated by a distance of 

(a) 4 m 

(b) 0.5 m 

(c) λ/2 

(d) 3λ/2

Answer 1

k = 2m × 0.008 cm^-1

We know that, k 

= 125cm

Now, (phase difference) = \(\frac{2π}{λ}\) × (path difference)