Question

A conductor of length 3m moving in a uniform magnetic field of strength 100 T. It covers a distance of 70 m in 5 sec. Its plane of motion makes an angle of 30° with direction of magnetic field. Calculate the emf induced in it.

Answer 1

Given: 

l = 3m, 

B = 100T, 

d = 70 m, 

t = 5 sec, 

θ = 30°, 

e = ? 

e = BlVsinθ 

V = \(\frac{d}{t}\) = \(\frac{70}{5}\) = 14m/s

V = 100 × 3 × 14 × sin 30° 

= 100 × 3 × 14 × \(\frac{1}{2}\)

e = 2100 V