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in Physics by (53.6k points)

Two tuning forks X and Y sounded together produce 10 beats per second. When Y is slightly loaded with wax, the number of beats reduces to 6 per second. If the frequency of X is 480 Hz, find that of Y.

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Frequency of x = 480 Hz

No. of beats with y = 10

∴ Frequency of y = 480 +10 or 480-10

i.e., 490 or 470

On loading y, number of beats = 6

Frequency of y after loading = 486 or 474 

∴ The frequency of y before loading can not be 470, because if it were 470 before loading, it must be less than 470 after loading. 

∴ Actual frequency of y = 490 Hz.

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