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Find \(\vec{a}\;.\;\vec{b}\; of\; |\vec{a}| = 3, |\vec{b}| = 4, |\vec{a} \times\vec{b}| = 6\)

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Find \(\vec{a}\;.\;\vec{b}\; of\; |\vec{a}| = 3, |\vec{b}| = 4, |\vec{a} \times\vec{b}| = 6\)

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⇒ \((\vec{a}\vec{b})^2 = \sqrt{108}\)

= 6√3

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