Question

Minimum Z = 3x + 5y such that x +3y ≤ 3, x+y ≥ 2, x, y ≥0.

Answer 1

x + 3y = 3

x	3	0
y	0	1

0 + 0  3 false 

∴ shading away from 0

x + y = 2

x	0	2	1
y	2	0	1

0 + 0 2  false 

shading away from 0 

Away from 0 

corner points of feasible region are 

A (0,2); Z = 5 x 2 = 10 

B (1.5, 0.5); Z = 7 

C (3,0); Z = 3 x 3 = 9 

∴ Z is minimum at B (1.5,0.5) = 7.