x + 2y = 100
0 + 0 100
0 – 0 < 0
False 2x – y = 0
0 – 0 < 0
False
2x +y = 200
0 + 0 <200 True
ABCD is the solution .
At A (0,200), Z = 2 x 200 = 400
At B (50,100), Z = 50 + 2 x 100 = 250
At C (20,40), Z = 20 + 2x 40= 100
At D (0,50), Z = 2 x 50 =100
Z is maximised at A (0,200) = 400
Z is minimised at 2 points C (20,40) & D (0, 50) = 100