Question

A glass tube, sealed at both ends, is 100 cm long. It lies horizontally with the middle 10 cm containing mercury. The two ends of the tube contain air at 27°C and at a pressure 76 cm of mercury. The air column on one side is maintained at 0°C and the other side is maintained at 127°C. Calculate the length of the air column on the cooler side. Neglect the changes in the volume of mercury and of the glass.

Answer 1

2L + 10 = 100 => 2L = 90 => L = 45 cm
Applying combined gas eqn to part 1 of the tube

Applying combined gas eqn to part 2 of the tube

=> 18000 – 400 x = 12285 + 273 x

Length of air column on the cooler side = L – x = 45 – 8.49 = 36.51

Comments

What is x

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x = length of air column at cooler side be