Question

Figure shows a 2.0 V potentiometer Used for the determination of the internal resistance of a 1.5 V cell. The balance point of the cell in open circuit is 76.3 cm. When a resistor of 9.5 Ω is used in the external circuit of the cell, the balance point shifts to 64.8 cm length of the potentiometer wire. Determine the internal resistance of the cell.

Answer 1

It follows that the emf of the cell E is balanced against the potential difference across the length I₁ and the terminal potential difference V against the potential difference across the length I₂